Question

Question 1 (1 point) Choose the reducing sugars (select all that apply): СН,ОН СН,ОН не — о он н ОН НА // Н v H ОН НА у н н н ОН н ОН CH,OH 1 ОНОН а снион и онон н СН,ОН ОН —0, ОН ОН ОН CH2OH -о- слъ

Answer 1

Question 1.

41 Reducing Sugars Reclucing Sugars of Hemiacetals ie - H OH - XOR at ainomeric position, I theri it's reducing Sugas. Because hemicicetal gets Converts into aldehyde oo Ketone by ring oper equitlibrium! 1 Now . HY CH2017 vo Non-Reducing sugas 94 acetal is present at anomeric position H OR . RAOR There is no -oh Group Hence open Chain : equilibrium Cloesnt exist in this case. CH, OH RI OH 14 Vh hemiacetal present i t Hence Loy it / H , OH Reclucing Sugar H OH Wom CH.CH a FP 30 hX Acebal Oif you H OH H Hence novi-reducing H OH DH 14 ... sugar. CH.CH OH 014 04

CH₂011 애 pu Hemiacetal on Reducing Sugar CHOOH 0 011 Olt/ HV CHOH ОҢ