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A random sample of size 12 was taken from a normally distributed population with a population mean 28 and a population standa

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Answer #1

Solution :

Given that ,

mean = \mu = 28

standard deviation = \sigma = 4

n = 12

\mu\bar x = 28

\sigma\bar x =\sigma  / \sqrt n = 4/ \sqrt 12=1.155

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