Question

From their positions in the periodic table arrange the atoms in the following series in order of increasing electronegativity: Br, Cl, Ge, K. Sr Sr<K«Ge< Cl< Br OK S¥«Ge< Br<CI OK<5«< Br< Ge SK< Br< Cl<Ge C<Br«Ge<Sr<K

Answer 1

given

Br,Cl,Ge,K,Sr

we know that

electronegativity increases from left to right(i.e in periods) in the periodic table

electronegativity decreases from top to bottom(i.e in groups) in the periodic table

consider Br and Cl (same group)

Br is down the group of that Cl belongs to (electronegativity decreases)

so electronegativity of Br < Cl

consider K and Ge(same period)

Ge is to the rightmost of K (electronegativity increases )

so electronegativity of K < Ge

consider Br and Ge(same period)

Br is to the rightmost of Ge (electronegativity increases)

so electronegativity of Ge < Br

now

consider Sr and K

here Sr belongs to Ca group and Ca is next right to that of K

so

Ca has high electronegativity and thus Sr will be having slighter high electronegativity than K

and also K is alkali metal it has less electronegativity compared to that alkaline earth metal(Sr)

hence

K < Sr

consider Sr and Ga

Ga is rightmost to that of Ca so it has high electronegativity than Ca which results in high electronegativity than Sr

Sr < Ge

Now

order is

K < Sr < Ge < Br < Cl