Homework Answers
for the reaction, CO + 2H2 = CH3OH, the ICE ( initial, change, equilibrium) table would be -
CO
H2
CH3OH
I 0.45 0.57 0
C -x -2(x) x
-----------------------------------------------
E = 0.28 y z
y and z are concentration of H2 and CH3OH at equilibrium
0.45 - x = 0.28
so, x = 0.17
and y = 0.57 - 2*0.17 = 0.23
and z = x = 0.17
now, Keq = [CH3OH] / [CO] [H2]2 = 0.17 / (0.28)*(0.23)2 = 11.48
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