For a particular reaction at 203.3 °C, AG = 424.99 kJ/mol, and AS - 551.38 J/mol...
For a particular reaction, AH = -14.20 kJ/mol and AS = -198.5 J/(mol.K). Calculate AG for this reaction at 298 K. AG = 73.35 kJ/mol
For a particular reaction at 239.1 °C, AG = 363.40 kJ/mol, and AS = 739.34 J/mol. K). Calculate AG for this reaction at -19.0 °C. AGE 554.22 kJ/mol
For a particular reaction at 212.3 °C, AG = -889.99 kJ/mol, and AS = 385.90 J/(mol · K). Calculate AG for this reaction at -2.8 °C. AG= 193.97 kJ/mol
What is the value of K for this aqueous reaction at 298 K? A+B F C +D AG° = 21.71 kJ/mol K =
For a particular reaction at 247.1 °C, AG = -699.04 kJ, and AS = 244.36 J/K. Calculate AG for this reaction at - 78.9 °C. AG =
For a particular reaction at 156.7 °C, AG = 279.62 kJ, and AS = 253.74 J/K. Calculate AG for this reaction at 3.7 °C. AG = .
AG,O (25°C kJ/mol) ДнР (25°C kJ/mol) So Substance (25°C J/mol-K) NaNO, (s) -467.9 -367.0 116.5 NaNO2 (s) -358.7 -284.6 103.8 Cl2O (g) CI2OS (g) PbO (s) 80.3 97.9 266.2 -212.5 -198.3 309.8 -217.32 -187.89 68.7 CI2CRO2 (I) CI2CRO2 (g) -579.5 -510.8 221.8 -538.1 -501.6 329.8 Compute the AH°, AG°, and AS° for the reaction given below at two temperatures: 298 K and 315 K. PbCl2 (s)3NaNO2(s) PbO(s)NaNO3(s) +2NO(g) +2NaCl(s) At 298 K kJ ΔΗ' is AG° is kJ J/K AS...
can I get help with ALL THREE of these questions, please? A reaction has a standard free-energy change of -17.30 kJ mol-'(-4.135 kcal mol-'). Calculate the equilibrium constant for the reaction at 25°C. Kog What is the value of K for this aqueous reaction at 298 K? A+B= C+D AG° = 14.81 kJ/mol K= For a particular reaction at 189.0 °C, AG = -424.14 kJ, and AS = 149.31 J/K. Calculate AG for this reaction at -101.8 °C. AG =...
What is the value of K for this aqueous reaction at 298 K? A+B=C+D AG° = 29.82 kJ/mol K=
What is the value of K for this aqueous reaction at 298 K? A+B= C+D AG = 21.79 kJ/mol -6601