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Consider a “standard engineer” that weighs 75 kg and takes in food with a caloric content...

Consider a “standard engineer” that weighs 75 kg and takes in food with a caloric content of 500 Cal = 2.09 x 106 J. a) If this food were completely converted to heat, estimate the rise in the body temperature of the engineer. Assume the specific heat of the engineer is equivalent to that of liquid water, 4.18 J g^(–1) K^(–1) . b) If the heat were used to vaporize water from body tissue, what would be the mass loss of the engineer? The heat of vaporization of water is 44.0 kJ mol^(–1)

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75 3 75000 S00 cal = 204 x106 & Cp=4.18 K a) = m AT 2. 09 x 10T x 4. 18 75000 1 TAT 6. 67K AT = 1 moe HaO 44 x 10 b) mol 18 3

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