Question

can someone please help me solve this lab?

calorie since it takes 1.00 cal to rai at units for the amount of heat may be The specific heat of water is used to define the value of a calorie since it takes 1 the temperature of 1 gram of water 1°C. The measurement units for the amount converted using the conversion factor: 1 calorie = 4.184 Joules. The specific heats of several substances are shown in Table 1. Notice that liquid water hee very large specific heat compared to most other substances. Because each substance specific heat value, specific heat can be used to identify a substance. Substance Table 1 Specific heat values Substance Specific heat (cal/g•°C) Water (liquid) 1.00 Water (solid) 0.486 Water (gas) 0.481 Ethyl alcohol nyl alcohol 0.583 Air 0.239 Carbon (graphite) 0.169 Aluminum Iron Copper Lead Zinc Brass Specific heat (cal/g.°C) 0.214 0.107 0.0920 0.0311 0.0927 0.0908 Calorimeter In theory, to measure the specific heat of a solid such as a metal, the temperature of th can be measured before and after heating. Together with the mass of the metal, the specin be calculated. However, this method requires that the amount of metali 1

Answer 1

mass of metal = 68.54g mass of water = Mass cal (cup t water) - mass of cup = 81.983 - 2.033 (Ti) metal = 93.5°c (Tg) metal: 25.3°C (Ti) water = 20.3°c (Te) water = 25.3°c (1) roti Temperature change of water in calorimetu= Te - Ti s 25.3 - 20:3 C by & heat gained water 2 (m) water x S x AT = 39.90 5x 4.184 x 5 - TJ:671 KI (i) heat loss by metal O object = agesapa . heat gain watu -1. 671 KJ (iv) temperature change. of metal 25.3 - 93.5" -F6820 specific heat of metal heat loss (m) metax SXAT +1671.61=+68.54X (S)×(68.2) Is-0,25 7 4 1671.61 = (s) Tg-Té of metal =