Question

Lab-10: Calorimetry: Specific Heat of a Metal DATA SHEETS: Reference: Chapter Notes-10 and Lab Manual (Pages 64 to 70) Use the following You Tubes to get more information https://youtu.be/8gHFOL2990U https://youtu.be/HlvilF6MI9c Calculate the Specific Heat and identify the Metal Observation Mass Mass of Metal (ml): 87.87 g Mass of polystyrene cup (m2): 2.32 g Mass of cup with water (m3): 72.82 g Mass of water in the cup (m3-m2): 70.5 g Temperature Initial temp. of Metal (the boiling water temperature (t1): 99.5°C Final temp. Metal (temp of water after immersing the Metal in the cup) (t2): 37.5°c Temp. lost by Metal (t2-t1), AT METAL: -62.0°C Initial temp. of cold water in the polystyrene cup (t3): 24.0°C Temp. gained by Water (t2-t3), AT WATER: 13..5°C According to the Law of Conservation of Energy, the heat exchanged between the hot metal and cold water is equal (q=-a) Quantity of heat gained or lost = Mass x Specific heat x Temperature difference Heat gained by water (g) = Heat lost by Metal (-a) Heat gained by water (q) = M water X 1.00 cal/g °C XAT °C water Heat Lost by Metal (-q) = M metal X Sp. Heat metal X AT °C metal MWATER X 1.00 cal/g °C XATWATER°C = MMETAL X Sp. Heat METAL X ATMETAL°C

Answer 1

Selution -Big. fuam ih...Given_data-,- Muntat 10:59 Alfontes 13:56 Leal Maranata 87.87 AT'S hitat Sp Heatware 9°C. det sp. Heatmorat 1.col /9.. Bylow.of coniewatian.of.energy, Hwater. Sp Hentater. I frattt = Mmetal. N. ATCmetal 89.888X Keskuses get 27 70 5g I cal x 13.5% gro 2) 0.17469 call goc x = i. Specific heat of metal a 0.175_callye The metal could be Silicon

Hence, the specific heat capacity of the metal is 0.175 cal/g^oC and the metal could be silicon.

Answer 2

Okay can you help me as well. The numbers are exactly the same except the first number. Mass of metal (m1)