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1 Name Lab Section: Date: PreLab: Specific Heat and Heat of Fusion Instructions: Prepare for this lab activity by answering t
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Answer #1

1. 1 cal = 4.184 Joules

So, 1.00 cal/g.°C = 4.184 J/g.°C

2. Heat = mass × specific heat × change in temperature

= 95 = 700 × C × 10

C = 0.0136 cal/ g.K

3. Enthalpy of fusion of water = 334 J/g

Heat gained = mass × enthalpy of fusion

= 250 x 334

= 83500 Joule

Or 83.5 Kj

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