Question

lectrical Heat Equivalent Experiment lorimeter cup with electrical heater is used to warm up 50g of water. The voltage on the ating coil is measured to be 6V and the current is 3A. The heater is turned on for a time period f2 minutes. What is the electrical energy (in Joule) used in this experiment? (s A) 4.186J B) 33.7J C) 10800 : If 2 calories of heat is transferred as energy, how many Joules of energy is there? (assume all work is transferred as heat) 5) A) 4.18 J/Cal D) 2160J 2J C) 8.36J D) 83.6 J 3. Water is heated in a calorimeter cup to determine the electrical heat equivalent (EHE). A graph of electrical energy (E) versus change in temperature (AT) yields a slope of 642.59J/C. The mass of the inner aluminum cup is 20g and the mass of the water is 155g. The specific heats are given as: Ccu,-0.2 I 5 calgoC and cwater-l cal/g°C (15) I) what is mc? a) 175 J/Cal b) 175 Cal/'C c) 159.3 g'C II) What is the experimental value of electrical heat equivalent (EHE)? d) 159.3 CalC a) 4.03 J/Cal b) 4.18 CalJ 4.16 J/Ca d) 4.18 J/cal Lab# 10: Speed of Sound Experiment I. A sound created at the Sun will (5) A) take a long time to reach to the earth as sound travel very slowly in empty space B) reach to earth faster than expected as sound will be travelling very fast through empty space. c) never reach the earth. d) Divide the distance between the sun and the earth by the speed of sound at ℃ to find the time needed to reach the earth. 3. Light is a longitudinal wave, whereas sound is transverse.(5) A) True B) False 4. A tuning fork with frequency of 512 Hz is used in a speed of sound experiment. Assuming that the room temperature is 18 °C (ls) i) What is the speed of sound at 18°C i) what is the lengths of the air column for the second resonance positions at 18°C a) 342.38 m/s b) 340.53 m/s c) 331.40 m/s d) 346.57 cm/s a) 0.501 m b) 0.177 m c) 0.531 m d) cannot be found from the given information.

Answer 1

power of coil = VI Energy E = VIt = 6 times 3 times 2 times 60 = 2160 J W = JQ = 4.18 times 2 W = 8.36 J J = Joule's constant = 4.18 J/cal E = (m_AlC_Al + m_w c_w + m_c c_c) delta T m_c c_c = m_Ac s_Ac + m_w s_w m_c c_c = [20 times 0.215 + 155 times 1] mc = 159.5 J/c Never reach because it is longitudinal (medium necessary) were in volume if is not required by us, light is transernorce, sound is longitudinal. False