Question-1
Given that the Saturn V booster rocket is powered by 810700 L of pure decane
Given that density of pure decane is 808 kg/m3
1 m3 volume occupies 1000 L of solution
Hence the density of decane can also be written as 808 kg / 1000 L
This means
1000 L volume of decane solution contains 808 kg of decane
then 810700 L volume of decane solution contains
810700 x 808 /1000 = 655045.6 kgs = 655045600 grams ( 1 kg = 1000 grams)
We have the molar mass of decane = 142.29 g/mol
We can calculate the number of moles from the formula
No. of moles = Weight / Molar mass
Therefore number of moles of decane = 655045600 / 142.29 = 4603595.474 moles
Thus the required number of moles of decane present in 810700 L of pure decane is 4603595.474 moles
Instructions: Work in groups of up to four (4). Clearly print your first and last name...