1)
Molar mass of O2 = 32 g/mol
Molar mass of Xe = 131.3 g/mol
n(O2) = mass of O2/molar mass of O2
= 8.1/32
= 0.2531
n(Xe) = mass of Xe/molar mass of Xe
= 13.7/131.3
= 0.1043
n(O2),n1 = 0.2531 mol
n(Xe),n2 = 0.1043 mol
Total number of mol = n1+n2
= 0.2531 + 0.1043
= 0.3575 mol
a)
Partial pressure of each components are
p(O2),p1 = (n1*Ptotal)/total mol
= (0.2531 * 755)/0.3575
= 535 mmHg
Answer: 535 mmHg
b)
p(Xe),p2 = (n2*Ptotal)/total mol
= (0.1043 * 755)/0.3575
= 220. mmHg
Answer: 220. mmHg
Only 1 question at a time please
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