Question

A 0.060-kg tennis ball, moving with a speed of 5.0 m/s, has a head-on collision with a 8.0x10-2-kg ball initially moving in the same direction at a speed of 2.4 m/s.

Answer 1

Port(a) H ball 2 Kg => 0,064, +0.080, = 0.492 30+49 -34.6 12 According to Congorbation before callision. of momentum, Tennis batt m, 4+ m, 49= m, ,4 m, 220 o »smis o sams. m. 0.060kg m - 8x102 kg m=0.060kg >> 0.060XS+ 8x10^2x 9.4 = 6.0600, +8x1044 after collision Os @ų and by Newton's experimental laco of collision, y-V, recup-U2) ( Perfectally ellastic collision) → v - U = 1 (5-2.4) e-1 y - U = 2.6 egn + 3x eq" → 34, +44 -94.6 30-34 = 7.8 7 Y = 39.4 = 4.63 m/s from ean ③ = 4.63 -2.6 910-9.03 m/s Hence, Permis bade = 4 = 90 mis ball = Q = 4.6 mes

Part-B is the Hence. Tennis ball moving after collision in the direction of its mitial motion, option (a) The tennis ball moves in the directions of its initial motion. Part (C) & is the Hence 8x102kg ball also move in its direction Hence option ist de. & The ball moves in the direction of ots inittal motion is correct.