Question

Please show me the work thank you

3) An object is thrown upward with a speed of 12 m/s on the surface of planet X where the acceleration due to gravity is 1.5 m/s2. How long does it take for the object to reach the maximum height? A) 8.0 s B) 11 s C) 14 s D) 16 s

Answer 1

$v^2 - u^2 = 2 a s \\ \\ v = 0 m/s \\ \\ s = (-u^2/2a)$

acceleration is directed opposite to initial speed so we get negative in 'a'

so maximum height = 48 m

time taken = 12/1.5 = 8 sec

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