Question

earning Microsoft Edge Covalent Activity.dollocator assignment-taketaksegmentsensionerasiment take Top References Use the References to access important values if needed for this question The equilibrium constant for the following reaction is 6.50-10 at 298K 2NOBr(g) 2NO(g) + Brgle) If an equilibrium mixture of the three ces at 20 equilibrium concentration of Br contains 1.20 10 *M NOR ) and 2.08-10 MNO, what is the Submit An Rally Entre Grow more

Please explain how r you multiplying this,as I am not getting the right answer.

Answer 1

Solution :- 10 gW0Brg) = 290,8 tbreng ; 'Ke=650X163 at Equilibriums: 1.24x102 in 2-08x15m ?m applying law of Chemical quilibrum, the equilibrium Constant I, is given by Kc = [NO] [ Bor] [Nobo] = 6-50x103 = (2-0 81153 & Loor] - (1-24x102) 2 |6-50 X163 - 4-3264x[Br] 1.5376 > [br] - 6.50 x 108x15376 » [Br] = (2-31 x 103 m (1-24 ņ u. 326 Y

2 ZNO Brgy Z 200 g + Brzgj; K= 6-50x103 atequilibrums: 3.97410 ? m 2-658107m ?m applying law of Chemical equilibrums, Ke= [NO]? {Bor] - [No Br] 2 * 6-50X163 = (2-65810?) & (Brz] (3.97X102) 2 => 6-50Mlo} - 7.0225 *{Brz] 15.7609 => [Bra] 6.50 710 x 15.7609 7.0225 [Br] = [14.588 M 27 3.9 6-sot s