I have a cylinder on the ground. I want to know the velocity of a point...
I have a cylinder on the ground. I want to know the velocity of a point on the cylinder angle theta away from the point on the ground. Given the angular velocity of the cylinder, the radius of the cylinder, and the angle theta, how would I do this?
Homework Answers
Velocity of a point moving in circle of radius r at angular speed w = wr
Point of cylinder in contact of ground is at rest and all points on cylinder are rotating about this point in circles of different radius but at common angular speed. Hence speed of any point on cylinder is w times distance of point from the point of cylinder in contact with ground.
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Determine:
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I know the answer to a) is 37.7 m/s and the answer to b) is
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For c) here how I solve it.
Let’s find the range of the projectile:
that would be:
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= 37.7^2 / 9.8 * sin (2 x 53 degree)
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A cannonball is fired from the ground and lands on a hill as shown in the figure below: 35° 150 m The initial velocity of the cannonball as it exits the canon is 50 m/s and it is launched at an angle of 35 above the horizontal. The cannonball lands on the hillside 150 m away from the cannon in the horizontal direction (as shown). 2 pts - a) What are the x- and y-components of the initial velocity of...
A sphere and a steel cylinder (? = 7850 kg / m3),
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Determine:
a) An expression for the angular velocity
(?) given an angular velocity
?. If both systems start from rest, after 7s,
b) What is the angular velocity of the cylinder?
C) What is the angular velocity of the sphere?
Pure rolling analysis....
Rolling and slipping: A relative motion approach Mech Name HW-45 6. A cylinder of radius R is placed on top of a wooden board. They are initially at rest. The board is then pulled to the right by a constant horizontal force of magnitude F on a frictionless surface, The cvlinder is observed to roll counterclockwise without slipping cylinder wooden board on the board frictioniess surface At the instant that the board has speed vh, the center-of- mass of the...
I know the answer to a) is 37.7 m/s and the answer to b) is
28.36 m
For c) here how I solve it.
Let’s find the range of the projectile:
that would be:
R = Vo ^2 /g * sin (2 theta)
= 37.7^2 / 9.8 * sin (2 x 53 degree)
= 139.41 m
Since 139.41m is longer than 28.36m + 90mm, it lands on the on
the other side of the building.
Why is it not correct?...
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please I want the right answer If you'er not sure dont do it ,
Thanks
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A 30-cm tall solid cylinder of diameter 20 cm is standing on the ground. If the force exerted on the ground by the weight of the cylinder is 500 N, what is the density of the material of the cylinder? A solid sphere of mass M and radius R (l=(2/5)MR^2) is placed on lop of a friction less inclined The plane is 7.0 m long and is making an angle of 35 degrees from the horizontal. Assuming the...
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