Concept:- here we use Coulomb's law for force
between charges and find the component along x-axis using vector
component method, ***************************************************************************************************
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find something wrong... I will rectify the mistakes asap if
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In the figure particle 1 of charge +4e is above a floor by distance d-4.40 mm...
In the figure particle 1 of charge +4e is above a floor by distance d 4.80 mm and particle 2 of charge +7e is on the floor, at distance d2 -8.10 mm horizontally from particle 1. What is the x component of the electrostatic force on particle 2 due to particle 1? Number Units
in the figure particle 1 of charge +4e is above a floor by distance d -2.30 mm and part de 2 of charge +8e is on the fi or, at distance -B 2D mm ho zontally from partide 1 what is the xcomponent of the electrostatic force on particle 2 due to particle 1 7 Number 3.177e-24
Chapter 21, Problem 039 In the figure particle 1 of charge +Se is above a floor by distance di-4.30 mm and particle 2 of charge +6e is on the floor, at distance d2-7.30 mm horizontally from particle 1. What is the x component of the electrostatic force on particle 2 due to particle 1? Number Units the tolerance is +/-2%
Chapter 21, Problem 039 In the figure particle 1 of charge +5e is above a floor by distance d1 = 2.00 mm and particle 2 of charge +6e is on the floor, at distance d2 = 6.50 mm horizontally from particle 1 What is the x component of the electrostatic force on particle 2 due to particle 1? Number Units the tolerance is +/-2%
In the figure particle 1 of charge +6e is above a floor by distance di 4.00 mm and particle 2 of charge +Be is on the floor, at distance d2-7.60 mm horizontally from particle 1. What is the x component of the electrostatic force on particle 2 due to particle 1
hapter 21, Problem 039 in the figure particle 1 of charge +6e is above a floor by distance d, What is the x component of the electrostatic force on particle 2 due to partide 1 charge +6e is above a floor by distance d, - 2.80 mm and particle 2 of charge +Be is on the floor, at distance dy- 8,70 mm horizontaly from partide charge + Be is cn
PRINTER VERSION BACK NEXT Question 3 Your answer is partially correct. Try again. In the figure particle 1 of charge + 4e is above a floor by distance di = 2.20 mm and particle 2 of charge +8e is on the floor, at distance d2 = 6.20 mm horizontally from particle 1. What is the x component of the electrostatic force on particle 2 due to particle 1? Number 1.0000000000000000000 units the tolerance is +/-2%
In the figure particle 1 of charge q1--8.27q and particle 2 of charge d2- +3.67q are fixed to an x axis. As a multiple of distance L, at what coordinate on the axis is the net electric field of the particles zero? ร้า 92 Number1.508 the tolerance is +/-296 Click if you would like to Show Work for this question: Units No units Open Show Work
Question 2 Your answer is partially correct. Try again. How many electrons would have to be removed from a coin to leave it with a charge of +6.0 x 10-8 c? Number 13750000000000 Units T No units the tolerance is +/-2% Question 3 Your answer is partially correct. Try again. In the figure particle 1 of charge +4e is above a floor by distance di = 2.20 mm and particle 2 of charge +8e is on the floor, at distance...
In the figure particle 1 of charge Q, - -7.17q and particle 2 of charge 92 +3.57q are fixed to an x axis. As a multiple of distance L, at what coondinate on the asis s he net eletnc h Units( 0.1 the tolerance is +/-2% Click if you would like to Show Work for this question: Open Show Work