Question

A soccer player extends her lower leg in a kicking motion by exerting a force with the muscle above the knee in the front of her leg. Suppose she produces an angular acceleration of 32 rad/s2 and her lower leg has a moment of inertia of 0.75 kg⋅m2 . What is the force, in newtons, exerted by the muscle if its effective perpendicular lever arm is 2.05 cm? $sig.gif?tid=8O75-6C-7E-4A-961B-22885$ F =

Answer 1

SOLUTION :

Formula for torque

Torque = Moment of inertia* angular acceleration

=> Torque = 0.75*32

Another formula for torque

Torque = F*d

Solving for Force

=> 0.75*32 = F * (2.05 *10^-2)

=> F = 0.75*32/(2.05/10^-2)

=> Force = 1170. 7 N ​​