How many calories are required to heat 25.0 g of platinum from 24.5 °C to 75°C...

Question

Question

Answer 1

Answer #1

Q = mc∆T

Q = heat energy (Joules, J), m = mass of a substance (g)

c = specific heat (units J/g∙^oC), ∆ is a symbol meaning "the change in"

∆T = change in temperature (^oC Celcius)

m = 25 gm c = 0.139 J/g∙^oC ∆T = 75 ^oC - 24.5 ^oC = 50.5 ^oC

Q = 25 gm x 0.139 J/g∙^oC x 50.5 ^oC

Q = 175.487 Joules

The answer was given in Calories. Hence we should convert Joules to calories.

1 Joules = 0.239 calories

175.487 Joules = 42 Calories

Hence option C is correct answer

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Answer 2

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