Homework Answers
Ksp of Pb3(PO4)2 = 3.0 x 10^-44
Pb3(PO4)2 (s) ------------> 3 Pb2+ (aq) + 2 PO43- (aq)
Ksp = [Pb2+]^3[PO43-]^2
3.0 x 10^-44 = [Pb2+]^3 (7.94 x 10^-3)^2
[Pb2+] = 7.807 x 10^-14 M
PbS -------------> Pb2+ + S2-
Ksp = [Pb2+][S2-]
8.4 x 10^-28 = (7.807 x 10^-14) [S2-]
[S2-] = 1.08 x 10^-14 M
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