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When a 27.9 mL sample of a 0.301 M aqueous hydrocyanic acid solution is titrated with a 0.358 M aqueous sodium hydroxide solu
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Answer #1

HCN + NaOH - Na CN + H₂O moles of HCN = Volx Molarity = 0.027 9 x 0.301 =8.398x10-3 moles = 0.008u molar moles of NaOH = 0.03

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