Question

Dehydration of Alcohols Dehydration of 2-Methylcyclohexanol Prelaboratory Mole Calculations Calculate the theoretical yield of the cyclohexenes products in both moles and grams. One mole of the starting alcohol gives one mole the mixture of isomers. You are using 1.0 mL of 2-methylcyclohexanol and 0.5 mL of the catalyst, H3PO4. No calculation is needed for the catalyst. CHE CH3 CH3 OH Н,РО, Third product CH2 + one double bond H2O heat 2-methylcyclohexanol bp 165-168°C d=0.93 g/mL 1-methylcyclohexene bp 110°C 3-methylcyclohexene bp 104 C

Answer 1

Answer:- CH3 CH .OH Third H₂PO4 Product tho СНІ, 2-methylcyclohexanol One double bond BP 165-16806 d = 0'93 91 ml Given. " volume do 2 methylly clohexanol = 1.0m) Now, Molon mass of 2-methylcyclohexanol is 114 19 9 mole Hence, weight at a methylcyclohexanol = vxd - l.omi X 0.93 0.93 gm. Now moles at 2-methylcyclohexanol is equal to 0'93 11419 Weight = e = 0.008 mole molaw mass Since I mole do 2-methyl exclohexanol gives Imole the mixture at isomer. (cyclohexene) do Hence 0.008 mole at 2 methylcyclohexanol will give 0.008 mule mixture to isomer. Now Height a mixture at isomer = 0.008 y 96.17 = 0.769 gm