Question

yet an experiment only formed 14 of product Cactual yield), thus the percent yield of produs experiment is 1.4/2.0x100 = 70% % yield actual yield theoretical weld X 100 You can rearrange this equation to calculate the tual yield of given the % and theoretical yields, or the theoretical yield if given the % and actual yields. Let's Practice: 1. Answer the following questions based on the reaction below (5pts) 2 NaCl - MgO - Na2O + MgCl2 a. What is the theoretical yield of sodium oxide (in grams) ir 24.0 grams of sodium chloride reacts with 10.5g of magnesium oxide? (1.25pts) b. If 10.5 g of Naz0 is formed during the reaction in part (a), what is the percent yield? (1.25pts) C. A student carried out the reaction in part (a) and got 92% yield of Na20. What is the student's actual yield? (1.25pts) d. What is the theoretical yield if the reaction above is 98.0% efficient and yields 154g Na20 when 10.0 g of Mgo completely reacts with an excess of NaCl? (1.25pts)

Answer 1

classmate Date 1 a) aNacht Mgo Nago + reg2 Molecular cueight of Race y 23 +35.52 58.5 Mgo 24+ 16 = 40 Nago 27237 0 16-62 Mga + 24 + 2x 35.5=95 Now 2400 g Nall- 24/58.5= 0.41 mole Nall. - 10.5 g ligo = 10.5/40 -0.2625 mol mio Here Imola Nall reach with one mol Mgo. This Nall has the limiting weight Now - 2x585 g Nall siner 62 9 Nago. 24 g Nace ginen (62X24)/(2x5815) 2 12 72 8 Nago. This threat cal weight of Nago = 12.72 G. 6) Naw Nago is formed a 10.59 Thus, % yiels = (10.5 100 % = 82.56% C Now, % gield - 92% Tuy the mans of Nargo = 12 72 X 92% Ell 708 T. Actual yield = 11.70g of Nago. d Now , 40 8 rego gives 62 g Nago. 2 og mego grues (62x 10/40= 155 & Nago Wond, 98% efficient. Thus thereo Heal yield - 15.5098% • 15.19 8 Nazo.