Question

Tou can rearrange tus eyuduunI LO Cdicuide the actual yielu i given ute y anu meureutai yleius, ur une theoretical yield if given the % and actual yields. Let's Practice: 1. Answer the following questions based on the reaction below (Spts) 2 NaCl + Mgo → Na2O + MgCl, a. What is the theoretical yield of sodium oxide (in grams) if 24.0 grams of sodium chloride reacts with 10.5g of magnesium oxide? (1.2 5pts) b. If 10.5 g of Na2O is formed during the reaction in part (a), what is the percent yield? (1.25pts) C. A student carried out the reaction in part (a) and got 92% yield of Na,o. What is the student's actual yield? (1.25pts) d. What is the theoretical yield if the reaction above is 98.0% efficient and yields 15.4 g Na, when 10.0 g of Mgo completely reacts with an excess of NaCl? (1.25pts)

Answer 1

1) e nada mgo - Nao angela a) modes of wadl= 21. o ochlorides moles of Mgo = 1 * 0.26 1) 2 moles of Nail gives I mole of Ngo Bil4l moles of Nael gives - 180141 0.205 moles of Ngo Nad is the limiting reagent. Theoretical yield of Nag = molestimolanman = 0.205*62 = 12.719 6) percent yield 0 percent yield = actual yield x100 - Theoretical field = 10.5 x100 1271 = 82.67. [DO c) 92% = Actualyield xloo 12.11 I actual yield = 92*12.11 = 1.699 d) molee of mgo= 100 0 248 moles moles of mgo = moles of Nao mans of Nao = molesx molarmas = 0.248x62 40:3 F 15.3769 = 1549 984 efficient gives --151449 too y efficient gives > 1514X100 15.719 Theoretical field of the reaction = 15.119