Question

Consumer Reports uses a 100-point customer satisfaction score to rate the nations major chain stores. Assume that from past
c. What is the sample standard deviation (to 2 decimals)? 12 should be rejected d. Construct a hypothesis test to determine w
02 Satisfaction Score Formula Parta Mean WNA Part b Variance ANA Parts Standard Deviation #N/A ÖR OWN 888888888989 Part d Deg
Degrees of Freedom WNA Hypothesized Standard Deviation Chi Square Test Statistics WNA Lower-Tail p-value Upper-Tail p-value T
0 0
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Answer #1

sample size (n) = 15

necessary calculation table:-

x_{i} (C- )
96 148.84
90 38.44
81 7.84
77 46.24
95 125.44
97 174.24
80 14.44
80 14.44
80 14.44
94 104.04
83 0.64
80 14.44
96 148.84
66 316.84
62 475.24
sum = 1257 sum=1644.4

sample mean :- ña IX m 1257 - 15 3.8 . © sample variance: - 02 Elain² 1644.4 17:46 15-1 ml 1 deviation: sample standard 1084

degrees of freedom = (n-1) = (15-1) = 14

p value = 0.6944 [ using minitab ]

decision:-

p value = 0.6944 > 0.05.

so, we fail to reject the null hypothesis.

conclusion:-

the hypothesis that the population standard deviation is 12 can not be rejected .

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