Question

** A shipment of limestone blocks has a density of 2700 kg/mº and a compressive strength of 250 MPa. The blocks are cubical with a side length of 30.0 cm. How many of these blocks can you stack up before the bottom one cracks?

Please show a full solution. Thanks.

Answer 1

Mass= density×volume

Pressure=Force/Area

DATE PAGE NO Cubical block of sede - a=30cm = 0.3om Density of block, S = 2700 kg/m Mass of each block, n = 8 (volume) m = sa - = 2700 x 10.3013 - =72.9 kg Weigh Weight of each block , W = mg het No. of blocks be N on the bottom block that can be stack on it without cracking it 10% Total force on the su bottom block - F = long Surface area of the face of block A = a² compressive stlength = 250 Mla - CS) = 250 N 106 Pa C.S. = F - Area of face 250 x 100 = N*72.9 x 9.8. - 20:30) N = 31494.08 -531494