Question

pH of solution when 25.00 mL of o. 100M ammonia solution is treated with 10.00mL of 0.500 M hydro- Chloric acio? pkb for ammonia is 4.76. 0.0251x 0.100 mol = 0.0025 mol ammonia soln. 0.010.x 0.5oomol 0.005 mol HCL Total volume = 35.00 ML 0.055L

Answer 1

NH₂ concentration = 25 mL y oloom = 2.5 mmol & HU concentration a 100mm x 0.500m2 s mamol NHL t că - How NH₃ + | 2.5 mmol -2.5 mmol HCl 5 mmol - 2.5 mmol +2.50 2.5 +2.5 2.5 mmol 2.5 mmol The solution having 2.5 mmol of HU in excess therefore pH of solution isi depends on the concentration of HU in total volume of solution of HU= Number of millimde Then concentration - Total volume 9.9 mmol 2.5mmo 25+ 10.0me 3576 = 0.07142 mole of HQ Ž pH = -log (47) PH = -log (0.07142) pH = 1.166 pH a 1.15