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5.00 mL of 0.250 M ammonia (NH3) is titrated with 0.100 M hydrochloric acid (HCl). The...

5.00 mL of 0.250 M ammonia (NH3) is titrated with 0.100 M hydrochloric acid (HCl). The Kb for ammonia is 1.75 x 10-5. What is the pH of the solution after the addition of 25.00 mL of HCl?

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Answer #1

NH3 + Hill NIACI Moles of NH₃ = 0.005 yx 0.250 molka R = 0.00125 mol moles of Hel = 0.025 KX 0.100miley = 0.0025 mol moles of

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