Ka * Kb = Kw = 1.0 X 10-14
A 25.0 ml sample of a 0.100 M solution of aqueo us ammonia is titrated with a 0.125 M solution of HCI.
Calculate the pH of the solution after 0.00, 10.0, 20.0, 30.00, and 40.0 mL of acid have been added; Kb of NH3= 1.8 X 10-5 at 25 °C.
Hint: First find the moles after each 10.00 ml of acid is added. Then find the concentration after equilibrium is reached.
A 25.0 ml sample of a 0.100 M solution of aqueo us ammonia is titrated with a 0.125 M solution of HCI.
44. A 25.0 mL sample of a 0.100 M solution of aqueous trimethylamine is titrated with a 0.125 M solution of HCI. What is the pH of the solution after 10.0, 20.0 and 30.0 mL of acid have been added? Acids К. Acetic 1.76 x 105 Bases Кь Ammonia Methylamine Dimethylamine Trimethylamine 1.76 x 10 4.4x 104 5.9 x 104 6.46 x 105 Salts Кар 3.3 x 108 PbF2 PbCl2 1.7 x 10 5.3 х 10° CaF2
A 10.00 mL sample of 0.300 M NH3 is titrated with 0.100 M HCl (aq). what is the initial pH? Calculate the pH after the addition of 10.0, 20.0, 30.0 and 40.0 mL of HCl. The Kb for NH3 is 1.8 x 10^-5
E. Titration calculations 1. A 25.0-ml sample of 0.100 M HCl is titrated with 0.125 M NaOH. How many milliliters of the titrant will be need to reach the equivalence point? 2. A 25.0-ml sample of 0.100 M Ba(OH)2 is titrated with 0.125 M HCI. How many milliliters of the titrant will be need to reach the equivalence point? 3. For the following titrations, determine if the equivalence points will be acidic, basic, or neutral i. NH3 titrated with HCI...
5.00 mL of 0.250 M ammonia (NH3) is titrated with 0.100 M hydrochloric acid (HCl). The Kb for ammonia is 1.75 x 10-5 What is the pH of the ammonia solution prior to the addition of any HCl? What is the pH of the solution after 5.00 mL of HCl has been added?
Acid/Base titrations 10. 25.0 mL of 0.100 M H2A (a weak diprotic acid) is titrated with 0.200 M NaOH. What is the pH of the solution when 0.00 mL, 10.0 mL, 12.5 mL, 20.0 mL, 25.0 mL, and 40.0 mL E.S RaWeMA 5.83 x 10 8) have been added? (Ka1= 2.46 x 10, Ka2 ANSWER: 0 mL = 2.315, 10.0 mL= 4.211 (or 4.213), 12.5 mL = 5.422, 20.0 mL 7.410, 25.0 mL = 9.966, 40.0 mL = 12.664 11....
A 20.0-mL sample of 1.50 M NH3 is titrated with 0.15 M HCl. What is the pH of the solution after 12.00 mL of acid have been added to ammonia? Kb for NH3 = 1.8 × 10–5
5.00 mL of 0.250 M ammonia (NH3) is titrated with 0.100 M hydrochloric acid (HCl). The Kb for ammonia is 1.75 x 10-5. What is the pH of the solution after the addition of 25.00 mL of HCl?
40.0 ml of an acetic acid of unknown concentration is titrated with 0.100 M NaOH. After 20.0 mL of the base solution has been added, the pH in the titration flask is 5.10. What was the concentration of the original acetic acid solution? [Ka(CH3COOH) = 1.8 × 10–5]
A 20.0-mL sample of 1.50 M NH3 is titrated with 0.15 M HCl. What is the pH of the solution after 12.00 mL of acid have been added to ammonia? Kb for NH3 = 1.8 × 10–5 5.93 9.30 8.06 9.07 10.45
Consider the titration of 25.0 mL of 0.100 M HF with 0.125 M KOH. The Ka is 6.8 x 10-4 for HF. What is the pH after 20.0 mL of base are added? Please show steps.