Question

Find the indicated z-scores shown in the graph. Click to view page 1 of the Standard Normal Table. Click to view page 2 of the Standard Normal Table. 0.4793 0 .4793 z=> 0 Z? The Z-scores are (Use a comma to separate answers as needed. Round to two decimal places as needed.) ontents Resour uccess Enter your answer in the answer box. uccess - 34 of 3 ia Library pe here to search ASUS ZenBook

Answer 1

Total probability between two z-score -z and z = 0.4793 + 0.4793 = 0.9586

P(-z < Z < z) = 0.9586

P(Z < z) - P(Z < -z) = 0.9586

P(Z < z) - (1 - P(Z < z) ) = 0.9586

P(Z < z) - 1 + P(Z < z) = 0.9586

2 P(Z < z) = 1.9586

P(Z < z) = 0.9793

From Z table, z-score for the probability of 0.9793 is 2.04

The z-scores are = -2.04 , 2.04