Solution:
Given that,
Using standard normal table,
P(-z < Z < z) = 0.0233
P(Z < z) - P(Z < z) = 0.0233
2P(Z < z) - 1 = 0.0233
2P(Z < z) = 1 + 0.0233
2P(Z < z) = 1.0233
P(Z < z) = 1.0233 / 2 = 0.5116
P(Z < z) = 0.5116
- z = -0.69 , z = 0.69
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