Question

1.2. Assume the random variable X is normally distributed, with mean 40 and standard deviation 4. Find the 12th percentile The 12th percentile is (Round to two decimal places as needed) ments Guide oduction Enter your answer in the answer box and then click Check Answer Review/Exam All parts showing 011 # SA W OONITU

Answer 1

Given: $\fn_phv \mu$= 40 and standard deviation $\fn_phv \sigma$ = 4

We have asked to find the 12th percentile.

By using raw score formula we get-

12th percentile (X) = Z_0.12 * $\fn_phv \sigma$ + $\fn_phv \mu$

By using Z table we get -   Z_0.12 = -1.175

12th percentile (X) = (-1.175 * 4) + 40

= 35.30

Hence the 12th percentile is 35.30

Hope this will help you.Thank you :)