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9. A student collected the following data: Mass of gas = 0.800 g, temperature of the water bath = 95.0°C, barometric pressure
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(a) * & T: 950 p: 760 mm 250 me H2O = 0.059 Assuming no H2O prinRT - pv RT -> 760 x 2560 X 0.0821(95+275) - 0.25% M - 24.1702

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