3. The bond Cu-NH3 is stronger. This is why the NH3 ligand is able to displace the H2O. The reason lies in the fact that N is the better electron pair donor as compared to O.
4. The reaction that takes place is : NH3 +
H+
NH4+
Now NH4+ is not a good ligand at all because it no longer has an electron pair to donate to Cu. Therefore, it is replaced by H2O being the stronger ligand in this case
dulude cds Reat wofh At the end of reaction IV, the ligand around Cu is HO,...
Why wouldnt a weak base, such as NH3, work just as well as KOH
in (1)?
2.2 Is the question I have. I figured out
2.1 already.
Below is relevant info. Thanks!
2. (1) Describe how adding a solution of KOH to the original sulfide precipitate results in the separa- tion of Sn4+ ion from the other Group W cations. (2) Why wouldn't a weak base, such as aque- ous NH3, work just as well as aqueous KOH in (1)?...