The (Figure 1) shows two thin beams joined at right angles. The vertical beam is 12.0 kg and 1.00 m long and the horizontal beam is 29.0 kg and 2.00 m long. Neglect the lateral dimensions of the beams. Part A Find the center of gravity of the two joined beams. Express your answer in the form x,y, taking the origin at the corner where the beams join. Express your answers in meters. Enter your answers separated by a comma. Part B Calculate the gravitational torque on the joined beams about an axis through the corner. Express your answer with the appropriate units.
Solution,
A)
Center of gravity of horizontal section, (x1, y1) = (1, 0) m
Center of gravity of vertical section, (x2, y2) = (0, 0.5) m
Center of gravity, (x, y) = (m1x1 + m2x2) /(m1 + m2), (m1y1 + m2y2) /(m1 + m2)
(x, y) = (0.707, 0.146) m
B)
Torque, T = (m1 g) (L/2) = 29 x 9.8 x 1 = - 284.2 Nm
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The (Figure 1) shows two thin beams joined at right angles. The vertical beam is 12.0...
The (Figure 1) shows two thin beams joined at right angles. The
vertical beam is 16.0 kg and 1.00 m long and the horizontal beam is
26.0 kg and 2.00 m long. Neglect the lateral dimensions of the
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Part A
Find the center of gravity of the two joined beams. Express your
answer in the form x,y, taking the origin at the
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Part B
Calculate the gravitational torque on the joined beams about an...
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