Question

A projectile is launched from level ground at an angle of 30 degrees to the horizontal. If the magnitude of the launch velocity is 30 m/s, calculate the time rate of change in speed and radius of curvature when t=1, 2, and when the projectile is at its max height.

Please do the problem how the description says to do it below and put the answer neatly in a table format. Thank you.

2) A projectile is launched from level ground at an angle of 30° to the horizontal.f the magnitude of the launch velocity is 30 m/s, calculate the time rate of change in speed (v) and the radius of curvature (p) when: a) t 1 seconds b) The projectile reaches its maximum height c) 2 seconds For each part, start with a sketch of the particle, the velocity and acceleration vectors, and the x-y coordinates. Next, overlay the n-t coordinates (Not Shown) with en and êt labels. This will help you see angles and how to project vectors to the n-t directions. ia) (example of how to start each part)

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Answer #1

(a) at t= Vx = 3o Cas 30° = 25.98 m/s (25.98) = 10.93。 t=0 how 2 (2533) 2 Cone 가28 m し) at baignut point- 2 2 25s 82 675 W l o

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