Question

Post lab Questions: 1. A mixture of ethyl iodide (C2H5l, bp = 72.3°C) and water boils at 64°C. What weight of ethyl iodide would be carried over by 1 g of steam during steam distillation? 2. The condensate from a steam distillation contains 8 g of an unknown compound and 18 g of water. The mixture steam distilled at 98°C. What is the molecular weight of the unknown?

Answer 1

1. Answer: liven, Billion Dolut of Boilling polut of Cats1 = 72.3°C 12.20 Boilling point of water = 64°c weight of steam (Ho) = 1.0g. Molecular weight of C2H51 = 155.99 glueel Molecular weight of tho=18 g/mol. vapor pressure of steam af 64C = 187.5 mmg ripour pressure of Cats I = 339.9 mmeng' Weight of Cats i carried out by the steam is - Wt. of (als I Pochs 1 x Mol.wt. e Hs. I Wt. of the rap Potopapx Mol.ot. 4o. Wt. of GHI Pocas IX Mol, wt. of CHS I Pono vap x mor of hox n. of the rap = 339.9 mmy Hg x 15599 ylmet 187.5 mm x 18 max 1.09. r wt. of Chs I= 15.7 g = 187.5 mmilyx L. Answer: needed first we need to calculate for 1 gm of the unknown 18g 10 the mass of water compound as 8g Ohk nowy Compound = 225g water Hence, d.25 g water speeded for 1 g of unknown compound. The weight of water needed to transfer Ig of something by Steam distillation is given by the following equ". Weight = 18 × Pho Mol. wt. of substance (760-Pro) e where Pho = vapour pressure of tho werght = 18 x 7073 2.25 (760-707.3) I weight = 107g/mol. Hence molecular weight of the unknown is = 107 g/mol