Question

what mass of (nh4)2so4 must be mixed with 55.0kg of Kno3 to produce a fertilizer that has 15.4 mass% nitrogen

Answer 1

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mass of (NH₄)₂SO₄ required in kg =14.63 kg.

Let man of (NH4)₂Soy required a xkg man of mixture = (x + 55 kg may % of N in Nha) 524 = 28_X100 = 2121 132 100gm (NH4), Soy contain 21.21gm 1kg (nnusoy contain 0.2121 goo kg so an n kg (NH4), Soy contain 0.2121 x kg Given mass of KNO3 = 55.0kg in loi gm KNO3, man of N = 148m so in 55 kg KNO3 , mass of N = 14x55 ke=7.62 kg So we have the equation 05. 0.154 (2 +55) = 7.62 + 0.21212 0.1540 +8.43 = 7.62 +0.212134 or 0.85 = 0.05814 of x = 14.63 kg TexSS kg = 7.62 kg