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JUST DRAW THE GRAPH!!!!!!!!!!

Consider a Solow growth model with the formulation δ 0.0175 investment = 0.192,/K Y 0.384 /K Where δ is the rate of depreciation, K is level of capital, and Ý is the level of output. Adjust the line labeled Depreciation and the function labeled Investment to be consistent with the given model 5.0 4.5 3 4.0 3.5 3.0 2.5 2.0 Investment 1.5 브 1.0 0.5 epreciation 0.0

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Answer #1

6.00 5.00 4.00 Investment, Yand Depreciation - Investment Depreciation - 2.00 1.00 0.004 100 150 200 250 Capital

K Y I D x K
0 0.00 0.00 0.00
20 1.72 0.86 0.35
40 2.43 1.21 0.70
60 2.97 1.49 1.05
80 3.43 1.72 1.40
100 3.84 1.92 1.75
120 4.21 2.10 2.10
140 4.54 2.27 2.45
160 4.86 2.43 2.80
180 5.15 2.58 3.15
200 5.43 2.72 3.50

Depreciation = .0175 x K

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Answer #2

Find where the investment and depreciation cross. Then look under Y

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