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Calculate the isotonic and isoelectric pH of 0.03479 M tryptophan. Enter your answers to the hundredths place. phai p2 Amino
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Answer #1

Isoionic point [H+] = √ [(K1K2F + K1Kw) / K1 + F)]

[H+] = √ [(10-2.37 x 10-9.33 x 0.03479) + 10-2.37 x 1.0 x 10-14) / (10-2.37 + 0.03479)] = 0.00000133357

pH = -log[H+] = -log[ 0.00000133357 ] = 5.87

pH = 5.87 for isoionic point.

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Isoelectric point pI = 1/2 (pKa1 + pKa2) = 1/2 (2.37 + 9.33) = 5.85

Isoelectric pH = 5.85

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Calculate the isoionic and isoelectric pH of 0.03479 M Amino Acid phai рк tryptophan. Enter your answers to the hundredths pl

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