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Calculate the isoionic and isoelectric pH of 0.01869 M proline. Enter your answers to the hundredths place. pkal 2.16 pk 2 8.
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Answer #1

ki = Pkal 10 -1.952 = 10 = 0.0112 0112 K2= lo please 10 10.640 - Pics 10 lo. 640 10 2.29x10 2.29 xlo - F -0.01869M KiK F + K

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