8) Arrange these ions according to ionic radius. Largest to smallest. (K+, Ca^2+, S^2-, CI-, P^3-)
10) Highest to lowest ionization energy. (K, Na, Rb, Li)
8)
All of them are isoelectronic
the one with greater atomic number has greater number of protons and hence nuclear force is more and hence it will be smaller
So, greater atomic number implies smaller radius
Order of atomic number is:
P < S < Cl < K < Ca
So, order of radius is:
P3- > S2- > Cl- < K+ < Ca2+
Answer: P3- > S2- > Cl- < K+ < Ca2+
Only 1 question at a time please
8) Arrange these ions according to ionic radius. Largest to smallest. (K+, Ca^2+, S^2-, CI-, P^3-)...
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