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8) Arrange these ions according to ionic radius. Largest to smallest. (K+, Ca^2+, S^2-, CI-, P^3-)...

8) Arrange these ions according to ionic radius. Largest to smallest. (K+, Ca^2+, S^2-, CI-, P^3-)

10) Highest to lowest ionization energy. (K, Na, Rb, Li)

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Answer #1

8)

All of them are isoelectronic

the one with greater atomic number has greater number of protons and hence nuclear force is more and hence it will be smaller

So, greater atomic number implies smaller radius

Order of atomic number is:

P < S < Cl < K < Ca

So, order of radius is:

P3- > S2- > Cl- < K+ < Ca2+

Answer: P3- > S2- > Cl- < K+ < Ca2+

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