Question

please show all steps and most important, please explain what's going on here. I'm most confused about the last step, but my entire understanding of this problem could use work. thank you in advance

15) (7 points) Draw the intermediates (A and B) and the product (C) of the cyclopentene using the following reagents (no need to draw the mechanism). For each molecule (A, B and C), draw the stereochemistry of the 2 chiral centers that were formed A C В Нас Нас HBr HC0K Нас hu Br-Br Hас 1 eq. Hас— он Нас Sample final Hi everyone, A Sa

Answer 1

1st step is addition of HBr in presence of light gives anti Markovnikoffs product forms syn product A. Potassium tertiory butoxide abstracts proton from less hindered side loss of leaving group forms product B. Then addition of Br2 in MeOH gives anti product C.

Tight By Meon B Come