ANSWER : To solve this,
We will use the concept of marginal productivity of steel at two plants.
Steel sent to Greenville = 80
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The Return of Detroit City: Enpar manufactures engine parts for Ford using steel as an input....
The Return of Detroit City: Enpar manufactures engine parts for Ford using steel as an input. Enpar operates two plants, one in Detroit, MI and one in Greenville, SC. The production functions for the two Enpar plants are: Detroit: Qp = 20 5p -0.25 50? Greenville: QG = 40 SG -0.556? where Qp and Qo are the outputs of engine parts (in units) from the Detroit and Greenville plants, respectively. Sp and Sg are the amounts of steel for the...
Question 9 1 pts The Return of Detroit City: Enpar manufactures engine parts for Ford using steel as an input. Enpar operates two plants, one in Detroit, MI and one in Greenville, SC. The production functions for the two Enpar plants are: Detroit: Qu= 135p -0.25 S02 Greenville: QG= 4156 -0.5562 where Qp and QG are the outputs of engine parts (in units) from the Detroit and Greenville plants, respectively. Sp and SG are the amounts of steel for the...
Question 9 1 pts The Return of Detroit City: Enpar manufactures engine parts for Ford using steel as an input. Enpar operates two plants, one in Detroit, MI and one in Greenville, SC. The production functions for the two Enpar plants are: Detroit: Qd=26SD -0.25 SD? Greenville: QG=5456 -0.5562 where Qp and QG are the outputs of engine parts (in units) from the Detroit and Greenville plants, respectively. So and So are the amounts of steel for the two plants....