we have equation to calculate pH for salt of weak acid
for such salts
pH = 1/2 [pKw + pKa + log C]
pKa = 5.39
pH = 9.2
C = ?
9.2 = 1/2 [14 + 5.39 + log C]
18.4 = 14 + 5.39 + log C
18.4 = 19.39 + log C
- 0.99 = log C
C = 0.102 M
[NaA] = 0.102 M
NaA ---------> Na+ + A-
NaA dissociate completely so
[Na+] = [A-] = 0.102 M
[Na+] = 0.102 M
ANS:... 10- If a solution of the sodium salt of a weak acid has pH of...
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