Question

Enter your answer in the provided box. A buffer that contains 0.459 M base, B, and 0.202 M of its conjugate acid, BH, has a pH of 8.86. What is the pH after 0.0020 mol of HCl is added to 0.250 L of this solution? pH =

Answer 1

pOH = 14-pH = 14-8.86 POH-5.14 PO}} = РК, + 14 5.14 = pkot log ( 0.202 -202 0.459 pk = 5.496 Now is 0.0020 mol of He auce added to 0.250L of this sole. MAHT = NIBH+ + Nice - n = np - Nice - B + He BHT 3 NHU nhu nhu MBHt = 0.202 x 0.25 = 0.0505 BH - Moth mol L Np = 0.459 Mol x 0.25 = 0-1148mol 30-0505 - 0.0020 MBH+ = 0.0485 mol Now, dam, & ©

= 0.1148 - 0:0020 n'B = 0.1128 mol Now, pot = pko + logo pott og POH = 5.496 + log 3-0485 mol 0.25 L 01128 mo) L 0-25 on solving 5.13 pOH = pH = 14-poh pH = 8-87 B