Question

A 77 kg bike racer climbs a 1400-m-long section of road that has a slope of 4.3 ∘ By how much does his gravitational potential energy change during this climb?

Answer 1

mass m = 77 kg

angle = 4.3°

H

Then height gained is 1400 m times the sine of 4.3 degree.

So, that's h is ,

h = (1400 m)(sin 4.3°)

h= (1400 m)(0.0749787) = 104.9702 m

The gravitational potential energy gained is = mgh

Here g= 9.81 m/s^2

Put the values and calculate ,

= (77 kg)(9.81 m/s²)(104.9702 m)

= 79291.34 J (Answer)

I hope help you !!