Question

The answers are in red. Please explain all parts

According to a research institution, the average hotel price in a certain year was $101.47. Assume the population standard deviation is $18.00 and that a random sample of 36 hotels was selected. Complete parts a through d below. a. Calculate the standard error of the mean. 6- = $3 (Round to two decimal places as needed.) b. What is the probability that the sample mean will be less than $103? P(<$103) = 0.6950 (Round to four decimal places as needed.) c. What is the probability that the sample mean will be more than $105? P(x>$105) = 0.1197 (Round to four decimal places as needed.) d. What is the probability that the sample mean will be between $100 and $101? P(5100 sxs $101) = 0.1257 (Round to four decimal places as needed.)

Answer 1

standatd erce of the 18 mean a) Ans 3 : 18 6天 = 6 d=101-4子 18 103 I01 47 PC天<103 P ь) 18/V36 6/G P(20.51) ao from Ztable O.6g497 LO.6950 PC1O5)P 105-101.47 18/36 6N -P(z> 1-1766) = o.l1966 O.t197 ) PC100sxs101)-P100-101-47 く - く101-11 971 18/36 6N o-49 zs-a-1566 - (2s-O1566) P2o.49 O.43778 0.31207 O.(2571 0.1257