prioe in a certain year was $108.53. Assume the population standard deviation is $22.00 and that...
According to a research institution, the average hotel price in a certain year was $105.12. Assume the population standard deviation is $20.00 and that a random sample of 32 hotels was selected. Complete parts a through d below. a. Calculate the standard error of the mean. (Round to two decimal places as needed.) b. What is the probability that the sample mean will be less than $106? P(x<$106) (Round to four decimal places as needed.) c. What is the probability...
According to a research institution, the average hotel price in a certain year was $97.27. Assume the population standard deviation is $23.00 and that a random sample of 43 hotels was selected. Complete parts a through d below. a. Calculate the standard error of the mean. out - = $ 3.51 (Round to two decimal places as needed.) b. What is the probability that the sample mean will be less than $99? P[<<$99) = (Round to four decimal places as...
The answers are in red. Please explain all parts According to a research institution, the average hotel price in a certain year was $101.47. Assume the population standard deviation is $18.00 and that a random sample of 36 hotels was selected. Complete parts a through d below. a. Calculate the standard error of the mean. 6- = $3 (Round to two decimal places as needed.) b. What is the probability that the sample mean will be less than $103? P(<$103)...
The average weight of a professional football player in 2009 was 245.3 pounds. Assume the population standard deviation is 40 pounds. A random sample of 35 professional football players was selected. Complete parts a through e a. Calculate the standard error of the mean. = 6.76 (Round to two decimal places as needed.) b. What is the probability that the sample mean will be less than 236 pounds? P( <236) 0845 (Round to four decimal places as needed.) c. What...
According to a research institution, the average hotel price in a certain year was $100 21 Assume the population standard deviation is $17 00 and that a random sample of 4 hotels was selected Complete parts a through d befow a, calculate the standard error of the mean Round to two decimal places as needed ) b. What is the probability that the sample mean will be less than $1027 X < $102) : (Round to four decimal places as...
% 7.4.12-T Question Help Assume the average price for a movie is $11.62. Assume the population standard deviation is $0.55 and that a sample of 36 theaters was randomly selected. Complete parts a through d below. a. Calculate the standard error of the mean. 0- = 5.0917 (Round to four decimal places as needed.) b. What is the probability that the sample mean will be less than $11.79? P(x<$11.79) = 9678 (Round to four decimal places as needed.) c. What...
Assume that x has a normal distribution with the specified mean and standard deviation. Find the indicated probability. (Round your answer to four decimal places.) H = 48; 0 = 16 P(40 sxs 47) = Assume that x has a normal distribution with the specified mean and standard deviation. Find the indicated probability. (Round your answer to four decimal places.) u = 14.6; 0 = 3.3 P(8 SX s 12) = Assume that x has a normal distribution with the...
A normally distributed population has a mean of 475 and a standard deviation of 48. a. Determine the probability that a random sample of size 9 selected from this population will have a sample mean less than 451. b. Determine the probability that a random sample of size 16 selected from the population will have a sample mean greater than or equal to 498. a. P(X<451) = (Round to four decimal places as needed.) b. P(X2498) = 1 (Round to...
The answers are in red and thanks in advance The average weight of a professional football player in 2009 was 255.6 pounds. Assume the population standard deviation is 30 pounds. A random sample of 31 professional football players was selected. Complete parts a through e. a. Calculate the standard error of the mean G = 5.39 (Round to two decimal places as needed.) b. What is the probability that the sample mean will be less than 242 pounds? PX<242) =...
According to a certain organization, adults worked an average of 1,792 hours last year. Assume the population standard deviation is 410 hours and that a random sample of 50 adults was selected. Complete parts a through e below. O = 57.98 (Round to two decimal places as needed.) b. What is the probability that the sample mean will be more than 1,820 hours? P(X>1,820) = .3146 (Round to four decimal places as needed.) c. What is the probability that the...