The RMS velocity of a particle at temperature T and molecular mass M is given by
Vrms= √(3RT/M)
Therefore,
1) For Nitrogen,
M N= 14
TN = 140+273 = 413 K
Therefore, VrmsN =√(3R(413)/14) ------ { equation 1}
Now,
2) For Hydrogen,
MH = 2
TH=?
Therefore, VrmsH = √(3RT H/2) --------- { equation 2}
Hence, equating 1 and 2 -->
√(3R(413)/14)=√(3RT/2)
=> 413/14 = T/2
=> T H = 413/7 = 59 K = 59-273 °C = -214°C
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